A) \[\frac{1}{9\pi }\]
B) \[\frac{5}{6\pi }\]
C) \[\frac{1}{18\pi }\]
D) \[\frac{1}{36\pi }\]
Correct Answer: C
Solution :
\[V=\frac{4}{3}\pi \left( {{(10+h)}^{3}}-{{10}^{3}} \right)\] \[\frac{dV}{dt}=4\pi {{\left( 10+h \right)}^{2}}\frac{dh}{dt}\] \[-50=4\pi {{\left( 10+5 \right)}^{2}}\frac{dh}{dt}\] \[\Rightarrow \]\[\frac{dh}{dt}=-\frac{1}{18}\frac{cm}{\min }\]You need to login to perform this action.
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