A) \[{{H}_{2}}+B{{r}_{2}}\to 2HBr\]
B) \[{{H}_{2}}+C{{l}_{2}}\to 2HCl\]
C) \[{{H}_{2}}+{{F}_{2}}\to 2HF\]
D) \[{{H}_{2}}+{{I}_{2}}\to 2HI\]
Correct Answer: D
Solution :
\[{{H}_{2}}+{{I}_{2}}\rightleftharpoons \text{ }2HI\] In this reaction catalyst is required because \[{{I}_{2}}\] is a less reactive.
You need to login to perform this action.
You will be redirected in
3 sec
