JEE Main & Advanced JEE Main Paper (Held On 10-Jan-2019 Evening)

  • question_answer
    Elevation in the boiling point for 1 molar solution of glucose is 2 K. The depression in the freezing point for 2 molar solution of glucose in the same solvent is 2 K. The relation between \[{{K}_{b}}\] and \[{{K}_{f}}\] is: [JEE Main Online Paper (Held On 10-Jan-2019 Evening]

    A) \[{{K}_{b}}={{K}_{f}}\]                                 

    B) \[{{K}_{b}}\,=0.5\,\,{{K}_{f}}\]

    C) \[{{K}_{b}}\,=\,1.5\,{{K}_{f}}\]           

    D)                  \[{{K}_{b}}=2\,\,{{K}_{f}}\]

    Correct Answer: D

    Solution :

    \[\Delta {{T}_{b}}={{K}_{b}}m\] \[2={{K}_{b}}\times 1\] \[\therefore \,\,\,\text{ }{{K}_{b}}=2\] \[\Delta {{T}_{f}}={{K}_{f}}m\] \[2={{K}_{f}}\times 2\] \[\therefore \,\,\,\text{ }{{K}_{f}}=1\] \[\therefore \,\,\,\text{ }{{K}_{b}}=2{{K}_{f}}\]


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