JEE Main & Advanced JEE Main Paper (Held On 10-Jan-2019 Morning)

  • question_answer
    A 2 W carbon resistor is color coded with green, black, red and brown respectively. The maximum current which can be passed through this resistor is- [JEE Main Online Paper (Held On 10-Jan-2019 Morning]

    A) 0.4 mA                         

    B) 20 mA

    C) 63 mA              

    D)   100 mA

    Correct Answer: B

    Solution :

    From colour code table \[R=50\times {{10}^{2}}=500\,\Omega \] \[Power=2\text{ }watt\] \[2={{i}^{2}}R\] \[2={{i}^{2}}\times 5000\] \[\frac{0.4}{1000}\,=\,{{i}^{2}}\] \[i\,\,=\,\,\frac{2}{100}\,Amp\,\,=\,\,20\,mA\]


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