A) \[\frac{25}{16}\lambda \]
B) \[\frac{27}{20}\lambda \]
C) \[\frac{16}{25}\lambda \]
D) \[\frac{20}{27}\lambda \]
Correct Answer: D
Solution :
In a hydrogen atom when an electron jumps from M-Shell to N-shell then, \[\frac{1}{\lambda }=K\left( \frac{1}{{{2}^{2}}}-\frac{1}{{{3}^{2}}} \right)=\frac{5}{36}K\] ?(i) for N to L shell, \[\frac{1}{\lambda '}=K\left( \frac{1}{{{2}^{2}}}-\frac{1}{{{4}^{2}}} \right)=\frac{3}{16}K=\frac{3}{16}\times \frac{36}{5\lambda }=\frac{27}{20\lambda }\] \[\therefore \]\[\lambda '=\frac{20\lambda }{27}\]
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