A) \[{{10}^{-5}}rad/s\]
B) \[{{10}^{-1}}rad/s\]
C) \[1rad/s\]
D) \[{{10}^{-3}}rad/s\]
Correct Answer: D
Solution :
Angular frequency of the pendulum. \[\omega =\sqrt{\frac{{{g}_{eff}}}{l}},\frac{\Delta \omega }{\omega }=\frac{1}{2}\frac{\Delta {{g}_{eff}}}{{{g}_{eff}}}\] \[\Delta \omega =\frac{1}{2}\frac{2A\omega _{s}^{2}}{g}\omega =\frac{1}{2}\times \frac{2\times {{(1)}^{2}}\times {{(10)}^{-2}}}{10}\] \[={{10}^{-3}}rad/s\]
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