JEE Main & Advanced JEE Main Paper (Held On 11-Jan-2019 Evening)

  • question_answer
    In a double -slit experiment, green light \[(\,5303\text{ }\overset{o}{\mathop{\text{A}}}\,)\] falls on a double slit having a separation of 19.44\[\mu m\] and a width of 4.05\[\mu m\]. The number of bright fringes between the first and the second diffraction minima is [JEE  Main Online Paper (Held on 11-jan-2019 Evening)]

    A) 10                                            

    B) 04

    C) 05                                

    D)   09

    Correct Answer: C

    Solution :

    \[{{\lambda }_{g}}=5303\overset{o}{\mathop{\text{A}}}\,,\,\,d=19.44\mu m\],\[a=4.05\mu m\] For diffraction location of first minima;\[{{y}_{1}}=\frac{D\lambda }{a}\] Location of second minima, \[{{y}_{2}}=\frac{2D\lambda }{a}\] For interference,                                  \[d\sin \theta \approx \frac{d{{y}_{1}}}{D}=\frac{d\lambda }{a}=4.80\lambda \] Also,\[d\sin \theta '\frac{d{{y}_{2}}}{D}=\frac{2d\lambda }{a}=9.62\lambda \] Number of bright fringes correspond to n = 5, 6, 7, 8, 9. 


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