A) 1 : 3
B) 2 : 1
C) 3 : 1
D) 4 : 1
Correct Answer: C
Solution :
Let a be the first term and d be the common difference. Given,\[{{a}_{19}}=a+18d=0\]\[\Rightarrow \]\[a=-18d\] \[\therefore \]\[\frac{a+48d}{a+28d}=\frac{-18d+48d}{-18d+28d}=\frac{30d}{10d}=\frac{3}{1}\]You need to login to perform this action.
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