A) \[-18\,\mu C\]
B) \[-12\,\mu C\]
C) \[+12\,\mu C\]
D) \[+18\,\mu C\]
Correct Answer: D
Solution :
Let \[{{q}_{1}}\]and \[{{q}_{2}}\]be the charge on \[6\mu F\]and\[4\mu F\]respectively. \[{{q}_{1}}+{{q}_{2}}=q\] ...(i) Also, \[\frac{{{q}_{1}}}{{{C}_{1}}}=\frac{{{q}_{2}}}{{{C}_{2}}}\] ?(ii) [\[\because \]\[{{C}_{1}}\] and \[{{C}_{2}}\] are in parallel combination] \[\Rightarrow \]\[{{q}_{2}}=\frac{{{C}_{2}}}{{{C}_{1}}}{{q}_{1}}=\frac{4}{6}{{q}_{1}}\] ?(iii) Using (i) and (iii), \[\frac{10}{6}{{q}_{1}}=q\Rightarrow q=\frac{5}{3}{{q}_{1}}\Rightarrow {{q}_{1}}=\frac{3}{5}(30)=18\mu C\]You need to login to perform this action.
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