A) 60 g
B) 50 g
C) 40 g
D) 100 g
Correct Answer: C
Solution :
Let m be the mass of ice added to water. \[(m-20)L+mC\Delta {{T}_{1}}=50{{C}_{1}}\Delta {{T}_{2}}\] \[\Rightarrow \]\[(m-20)(334)+m\times 2.1(20)=50\times 4.2\times (40)\] \[\Rightarrow \]\[m(334+42)=5400+6680\] \[\Rightarrow \]\[m=40.1g\]You need to login to perform this action.
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