[JEE Main Online Paper (Held On 11-Jan-2019 Morning]
A) 4.0 mA
B) 0.0 mA
C) 6.0 mA
D) 6.7 mA
Correct Answer: B
Solution :
Net resistance of the circuit \[R={{R}_{1}}+\frac{{{R}_{2}}}{2}=1250\Omega \] Current drawn from battery,\[I=\frac{12}{1250}A\] Voltage across\[{{R}_{2}}=\frac{I}{2}\times {{R}_{2}}=\frac{12}{2\times 1250}\times 1500\] = 7.2 V < Zener voltage (10 V) Hence, zener diode is in reverse biased without break down. So, current through diode is 0 mA.
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