question_answer

If a reaction follows the Arrhenius equation, the plot In k vs 1/(RT) gives straight line with a gradient (-Y) unit. The energy required to activate the reactant is [JEE Main Online Paper (Held On 11-Jan-2019 Morning]

A) Y unit  

B)                           Y/R unit

C) YR unit             

D)   -Y unit.

Correct Answer: A

Solution :

According to Arrhenius equation, \[A{{e}^{-}}^{\frac{{{E}_{a}}}{RT}}\]or\[\ln \,k=\ln \,A-\frac{{{E}_{a}}}{RT}\] Comparing the above equation with straight line equation, \[y=mx+c,\]we get, slope \[(m)=-{{E}_{a}}\]ln k Intercept = ln A   Thus, slope should be \[{{E}_{a}}=Y.\]