A) \[{{K}_{2}}Mn{{O}_{4}},KMn{{O}_{4}}\text{and}\,S{{O}_{2}}\]
B) \[{{K}_{2}}Mn{{O}_{4}},KMn{{O}_{4}}\text{and}\,C{{l}_{2}}\]
C) \[{{K}_{3}}Mn{{O}_{4}},KMn{{O}_{4}}\text{and}\,C{{l}_{2}}\]
D) \[KMn{{O}_{4}},{{K}_{2}}Mn{{O}_{4}}\,\text{and}\,C{{l}_{2}}\]
Correct Answer: D
Solution :
\[\underset{(X)}{\mathop{2KMn{{O}_{4}}}}\,\xrightarrow[\Delta ]{513K}\underset{(Y)}{\mathop{{{K}_{2}}Mn{{O}_{4}}}}\,+Mn{{O}_{2}}+{{O}_{2(g)}}\] \[Mn{{O}_{2}}+4NaCl+4{{H}_{2}}S{{O}_{4}}\to MnC{{l}_{2}}+4NaHS{{O}_{4}}\] \[+2{{H}_{2}}O+C{{l}_{2(g)}}(Z)\]pungent gas
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