JEE Main & Advanced JEE Main Paper (Held on 12-4-2019 Afternoon)

  • question_answer
              Consider an electron in a hydrogen atom, revolving in its second excited state (having radius \[4.65\overset{\text{o}}{\mathop{\text{A}}}\,\]). The de-Broglie wavelength of this electron is : [JEE Main 12-4-2019 Afternoon]

    A) \[12.9\overset{\text{o}}{\mathop{\text{A}}}\,\]

    B) \[3.5\overset{\text{o}}{\mathop{\text{A}}}\,\]

    C) \[9.7\overset{\text{o}}{\mathop{\text{A}}}\,\]

    D)   \[6.6\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: C

    Solution :

    \[2\pi {{r}_{n}}=n{{\lambda }_{n}}\] \[{{\lambda }_{3}}=\frac{2\pi (4.65\times {{10}^{-10}})}{3}\] \[{{\lambda }_{3}}=9.7\overset{\text{o}}{\mathop{\text{A}}}\,\]


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