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JEE Main & Advanced JEE Main Paper (Held on 12-4-2019 Morning)

  • question_answer
    An ideal gas is allowed to expand from 1 L to 10 L against a constant external pressure of 1bar. The work done in kJ is :                                                               [JEE Main Held on 12-4-2019 Morning]

    A) -9.0                 

    B) +10.0

    C) -0.9

    D) -2.0

    Correct Answer: C

    Solution :

     \[W=-{{P}_{ext}}({{V}_{2}}-{{V}_{1}})\]           \[=-1bar\times (10-1)lit\]           \[=-9bar-lit\]           \[=-900J\]           \[=-0.9\,kJ\]              


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