[JEE Main Online Paper Held On 12-Jan-2019 Evening]
A) \[1.1\text{ }A,\text{ }0.4\text{ }A,\text{ }0.4\text{ }A\]
B) \[-0.4A,\,\,0.4A,\,\,1.1A\]
C) \[1.1\text{ }A,\,\,-0.4\text{ }A,\,\,0.4\text{ }A\]
D) \[0.4A,\,\,1.1A,\,\,0.4A\]
Correct Answer: A
Solution :
Applying KCL at junction \[{{P}_{1}},{{I}_{5}}={{I}_{6}}\Rightarrow {{I}_{6}}=0.4A\] From KCL at point \[R,{{I}_{1}}+{{I}_{2}}={{I}_{4}}\] \[\Rightarrow \]\[{{I}_{2}}={{I}_{4}}-{{I}_{1}}=0.8-(-0.3)=1.1A\] At point \[S,{{I}_{5}}+{{I}_{3}}={{I}_{4}}\Rightarrow {{I}_{3}}={{I}_{4}}-{{I}_{5}}\] \[\Rightarrow {{I}_{3}}=0.8-0.4=0.4A.\]
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