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JEE Main & Advanced JEE Main Paper (Held On 12-Jan-2019 Evening)

  • question_answer
    A long cylindrical vessel is half filled with a liquid. When the vessel is rotated about its own vertical axis, the liquid rises up near the wall. If the radius of vessel is 5 cm and its rotational speed is 2 rotations per second, then the difference in the heights between the centre and the sides, in cm, will be [JEE Main Online Paper Held On 12-Jan-2019 Evening]

    A) 0.4                               

    B) 2.0

    C) 0.1                               

    D)   1.2

    Correct Answer: B

    Solution :

    The linear speed of the liquid at the sides is \[r\omega \]. So, the difference in height is given as follows: \[2gh={{w}^{2}}{{r}^{2}}\] \[\Rightarrow \]\[h=\frac{{{(2\times 2\pi )}^{2}}{{(5\times {{10}^{-2}})}^{2}}}{2\times 10}\approx 0.02m\]


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