A) 0.4
B) 0.5
C) 0.6
D) 0.3
Correct Answer: C
Solution :
Modulation Index \[\mu =\frac{{{A}_{\max }}-{{A}_{\min }}}{{{A}_{\max }}+{{A}_{\min }}}=\frac{160-40}{160+40}=\frac{120}{200}=0.6\]f
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