A) 5
B) 1
C) 7
D) 3
Correct Answer: A
Solution :
\[\underset{Conc.}{\mathop{{{I}_{2}}+10HN{{O}_{3}}}}\,\to \underset{(Y)}{\mathop{2HI{{O}_{3}}}}\,+10N{{O}_{2}}+4{{H}_{2}}O\] Let oxidation state of I be x \[+1+x+3(-2)-0\] \[x=+5\]
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