A) 5
B) \[\frac{35}{3}\]
C) \[-\frac{35}{3}\]
D) \[-5\]
Correct Answer: A
Solution :
Let \[{{m}_{1}}=\]slope of line \[2x-3y+17=0\]and \[{{m}_{2}}=\] slope of line joining (7, 17) and \[(15,\beta )\] \[\therefore \]\[{{m}_{1}}=\frac{2}{3}\]and\[{{m}_{2}}=\frac{\beta -17}{15-7}=\frac{\beta -17}{8}\] Since, both the lines are perpendicular. \[\therefore \]\[{{m}_{1}}{{m}_{2}}=-1\] \[\Rightarrow \]\[\frac{2}{3}\times \frac{\beta -17}{8}=-1\Rightarrow \beta -17=-12\Rightarrow \beta =5\]
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