JEE Main & Advanced JEE Main Paper (Held On 12-Jan-2019 Morning)

  • question_answer
    If the sum of the deviations of 50 observations from 30 is 50, then the mean of these observations is [JEE Main Online Paper Held On 12-Jan-2019 Morning]

    A) 30                                

    B) 51   

    C) 31                                

    D)   50

    Correct Answer: C

    Solution :

    Here, \[\sum\limits_{i\,\,=\,\,1}^{50}{({{x}_{i}}-30)=50}\] \[\Rightarrow \sum\limits_{i=1}^{50}{{{x}_{i}}=50+50\times 30}\] \[\therefore \]Mean\[=\frac{\sum\limits_{i=1}^{50}{{{x}_{i}}}}{50}=\frac{50\times 31}{50}=31\]


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