JEE Main & Advanced JEE Main Paper (Held On 15 April 2018) Slot-I

  • question_answer
    One mode of an ideal monoatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, \[27{}^\circ C\]. The work done on the gas will be:   [JEE Online 15-04-2018]

    A) \[300R\,\,In\,\,6\]                     

    B) \[300R\]          

    C) \[300R\,\,In\,\,7\]                     

    D) \[300R\,\,In\,\,2\]         

    Correct Answer: D

    Solution :

    Work done in isothermal process is given as \[W=-nRT\,\,In\frac{V2}{{{V}_{1}}}\] \[W=R\times 300In\frac{{{P}_{1}}}{{{P}_{2}}}\] \[W=-R\times 300In\frac{P}{2P}\] \[W=300R\,\,In\,\,2\]


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