2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced JEE Main Paper (Held On 15 April 2018) Slot-I

  • question_answer
    An automobile, travelling at \[40km/h\], can be stopped at a distance of \[40m\]by applying brakes. If the same automobile is travelling at \[80km/h\], the minimum stopping distance, in metres, is (assume no skidding)                                                                                                     [JEE Online 15-04-2018]

    A) \[75m\]            

    B) \[160m\]          

    C) \[100m\]                      

    D) \[150m\]          

    Correct Answer: B

    Solution :

    Since stopping distance, \[s=\frac{{{v}^{2}}}{2a}\] For case \[1,40=\frac{{{(40\times \frac{5}{18})}^{2}}}{2a}..........(1)\] For case 2, \[s=\frac{{{(80\times \frac{5}{18})}^{2}}}{2a}...........(2)\] From (1) and (2), \[s=160m\]


You need to login to perform this action.
You will be redirected in 3 sec spinner