JEE Main & Advanced JEE Main Paper (Held On 15 April 2018) Slot-I

  • question_answer
    A charge \[Q\] is placed at a distance \[a/2\] above the centre of the square surface of edge \[a\] as shown in the figure. The electric flux through the square surface is:                                     [JEE Online 15-04-2018]

    A) \[\frac{Q}{3{{\in }_{0}}}\]              

    B) \[\frac{Q}{6{{\in }_{0}}}\]  

    C) \[\frac{Q}{2{{\in }_{0}}}\]              

    D) \[\frac{Q}{{{\in }_{0}}}\]    

    Correct Answer: B

    Solution :

    Draw an imaginary square enclosing that point charge at the centre. Then from gauss law,\[\phi =\frac{{{Q}_{in}}}{{{\in }_{o}}}\] This is the flux passing through all the six surfaces. Therefore through one surface, \[\frac{1}{6}th\] of this flux will pass.


You need to login to perform this action.
You will be redirected in 3 sec spinner