JEE Main & Advanced JEE Main Paper (Held On 15 April 2018) Slot-I

  • question_answer
    A Helmholtz coil has pair of loops, each with \[N\] turns and radius\[R\]. They are placed coaxially at distance \[R\] and the same current \[I\] flows through the loops in the same direction. The magnitude of magnetic field at \[P\], midway between the centres \[A\]and \[C\], is given by (Refer to figure):         [JEE Online 15-04-2018]

    A) \[\frac{4N{{\mu }_{0}}I}{{{5}^{3/2}}R}\]                      

    B) \[\frac{8N{{\mu }_{0}}I}{{{5}^{3/2}}R}\]          

    C) \[\frac{4N{{\mu }_{0}}I}{{{5}^{1/2}}R}\]                      

    D) \[\frac{8N{{\mu }_{0}}I}{{{5}^{1/2}}R}\]

    Correct Answer: B

    Solution :

    The magnetic field due to both the coils are in the same direction and equal in magnitude. The magnitude of the magnetic field due to one coil is give as \[B=\frac{{{\mu }_{o}}i{{R}^{2}}}{2{{({{R}^{2}}+{{(R/2)}^{2}})}^{3/2}}}\] \[B=\frac{4{{\mu }_{o}}i{{R}^{2}}}{5{{R}^{2}}}\] \[{{B}_{net}}=2B\] \[{{B}_{net}}=\frac{8{{\mu }_{o}}i{{R}^{2}}}{5{{R}^{2}}}\]


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