question_answer

\[\begin{align}   & \text{         }\left( \text{I} \right)\text{     }\left( \text{II} \right) \\  & \text{H - N - - -N - - -N} \\ \end{align}\] In hydrogen azide, the bond orders of bonds (I) and (II) are _________.        [JEE Online 15-04-2018]

A) \[\text{(i)-2, (ii)-2}\]    

B) \[(i)->2,\,\,(ii)->2\]     

C) \[(i)->2,\,\,(ii)-<2\]     

D) \[(i)-<2,\,\,(ii)<2\]

Correct Answer: A

Solution :

As in the resonance structure of hydrogen azide, it can be seen than number of bond is \[\le 2\] for bond \[(i)\] Hence its bond order will be\[<2\] Whereas for bond\[(ii)\], number of bond\[\ge 2\] Thus its bond order will be \[>2\].