A) (i) \[\text{NaB}{{\text{H}}_{4}}\], (ii) Raney\[Ni/{{H}_{2}}\] (iii) \[{{H}_{3}}{{O}^{+}}\]
B) (i) \[{{B}_{2}}{{H}_{6}}\] (ii) \[SnC{{l}_{2}}/HCl\] (iii)\[{{H}_{3}}{{O}^{+}}\]
C) (i) \[LiAl{{H}_{4}}\] (ii) \[{{H}_{3}}{{O}^{+}}\]
D) (i) \[{{B}_{2}}{{H}_{6}}\] (ii) \[\text{DIBAL-H}\] (iii)\[{{\text{H}}_{3}}{{O}^{+}}\]
Correct Answer: D
Solution :
The reagent required for the following reaction is \[{{B}_{2}}{{H}_{6}},DIBAL-H,{{H}_{3}}{{O}^{+}}\].
You need to login to perform this action.
You will be redirected in
3 sec
