question_answer

A capacitor \[{{C}_{1}}=10\mu F\] is charged up to a voltage \[V=60V\] by connecting it to battery \[B\] through switch (1), Now \[{{C}_{1}}\] is disconnected from battery and connected to a circuit consisting of two uncharged capacitors \[{{C}_{2}}=3.0\mu F\] and \[P{{C}_{3}}=6.0\mu F\] through a switch (2) as shown in the figure. The sum of final charges on \[{{C}_{2}}\]and \[{{C}_{3}}\]is: [JEE Online 15-04-2018 (II)]

A)                     \[36\mu C\]                       

B) \[20\mu C\]       

C) \[54\mu C\]       

D)          \[40\mu C\]