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JEE Main & Advanced JEE Main Paper (Held On 15 April 2018) Slot-II

  • question_answer
    Two simple harmonic motions, as shown, are at right angles. They are combined to form Lissajous figures. \[x(t)=A\sin (at+\delta )\] \[y(t)=B\sin (bt)\] Identify the correct match below                                                                                             [JEE Online 15-04-2018 (II)]

    A) \[\text{Parameters: A=B, a=2b;}\delta \text{=}\frac{\pi }{2};Curve:Circle\]

    B) \[\text{Parameters: A=B, a=b;}\delta \text{=}\frac{\pi }{2};Curve:line\]

    C) \[\text{Parameters: A}\ne \text{B, a=b; }\delta \text{=}\frac{\pi }{2};Curve:\text{Ellipse}\]

    D) \[\text{Parameters:}A\ne B,a=b;\delta =0;\text{Curve : Parabola}\]

    Correct Answer: C

    Solution :

    Lissajous curves take common shapes depending on the variables in the expressions. \[x=A\sin (at+\delta )\] \[y=B\sin (bt+r)\] If \[A\ne B\And a=b\] we obtain ellipse


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