A) Zero
B) Six
C) Four
D) Two
Correct Answer: C
Solution :
The total number of optically active compounds formed is four. The product has two chiral C atoms (marked with asterik). Thus, it has \[{{2}^{n}}={{2}^{2}}=4\] stereoisomers.
You need to login to perform this action.
You will be redirected in
3 sec
