A) \[{{[ZnC{{l}_{4}}]}^{2-}}>{{[NiC{{l}_{4}}]}^{2-}}>{{[CoC{{l}_{4}}]}^{2-}}>{{[MnC{{l}_{4}}]}^{2-}}\]
B) \[{{[CoC{{l}_{4}}]}^{2-}}>{{[MnC{{l}_{4}}]}^{2-}}>{{[NiC{{l}_{4}}]}^{2-}}>{{[ZnC{{l}_{4}}]}^{2-}}\]
C) \[{{[NiC{{l}_{4}}]}^{2-}}>{{[CoC{{l}_{4}}]}^{2-}}>{{[MnC{{l}_{4}}]}^{2-}}>{{[ZnC{{l}_{4}}]}^{2-}}\]
D) \[{{[MnC{{l}_{4}}]}^{2-}}>{{[CoC{{l}_{4}}]}^{2-}}>{{[NiC{{l}_{4}}]}^{2-}}>{{[ZnC{{l}_{4}}]}^{2-}}\]
Correct Answer: D
Solution :
The complex having higher number of unpaired electrons will have higher value of spin-only magnetic moment. The correct order of spin-only magnetic moments is \[{{[MnC{{l}_{4}}]}^{2-}}>{{[CoC{{l}_{4}}]}^{2-}}>{{[NiC{{l}_{4}}]}^{2-}}>{{[ZnC{{l}_{4}}]}^{2-}}\]. In theses complexes, the central metal ion is in \[+2\] oxidation state. \[Z{{n}^{2+}}\] has \[3{{d}^{10}}\] outer electronic configuration with 0 unpaired electrons. \[N{{i}^{2+}}\] has \[3{{d}^{8}}\] outer electronic configuration with 2 unpaired electrons. \[C{{o}^{2+}}\] has \[3{{d}^{7}}\] outer electronic configuration with 3 unpaired electrons. \[M{{n}^{2+}}\] has \[3{{d}^{5}}\] outer electronic configuration with 5 unpaired electrons.
You need to login to perform this action.
You will be redirected in
3 sec
