A) Y will have higher dipole moment and higher boiling point than X
B) Y will have higher dipole moment and lower boiling point than X
C) X will have lower dipole moment and lower boiling point than Y
D) X will have higher dipole moment and higher boiling point than Y
Correct Answer: D
Solution :
When 2-butyne is treated with \[{{H}_{2}}\]/Lindlar's catalyst, compound X (cis-2-butene) is produced as the major product and when treated with Na/liq. \[N{{H}_{3}}\] it produces Y (trans-2-butene) as the major product. X will have higher dipole moment and higher boiling point than Y. C is isomer will have higher dipole moment and higher boiling point than trans. trans-2-butene has centre of inversion and hence, zero dipole moment. The boiling points of c is and trans isomers of 2-butene are 277 K and 274 K respectively.
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