JEE Main & Advanced JEE Main Paper (Held On 15 April 2018) Slot-II

  • question_answer
    If \[f(x)\] is a quadratic expression such that \[f(1)+f(2)=0\], and \[-1\] is a root of \[f(x)=0\], then the other root of \[f(x)=0\] is                                        [JEE Online 15-04-2018 (II)]

    A)         \[-\frac{5}{8}\]                                 

    B) \[-\frac{8}{5}\] 

    C) \[\frac{5}{8}\]                   

    D)          \[\frac{8}{5}\]

    Correct Answer: D

    Solution :

    Let \[\alpha \]and \[\beta =-1\]be the roots of the polynomial, then we have \[f(x)={{x}^{2}}+(1-\alpha )x-\alpha \] \[f(1)=2-2\alpha .....i\] \[f(2)=6-3\alpha ......ii\] \[f(1)+f(2)=0\Rightarrow 2-2\alpha +6-3\alpha =0\Rightarrow \alpha =\frac{8}{5}\] So the other root is \[\frac{8}{5}\] So the correct answer is option D.


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