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JEE Main & Advanced JEE Main Paper (Held On 16 April 2018)

  • question_answer
    A power transmission line feeds input power at 2300 V to a step down transformer with its primary windings having 4000 turns, giving the output power at 230 V. If the current in the primary of the transformer is 5A, and its efficiency is 90%, the output current would be:      [JEE Main 16-4-2018]

    A)  20 A               

    B)  45 A

    C)  45 A               

    D)  25 A

    Correct Answer: C

    Solution :

     Power \[={{V}_{2}}{{I}_{2}}=\eta \times Powe{{r}_{in}}=\frac{90}{100}\times 2300\times 5\] \[{{I}_{2}}=\frac{90\times 23\times 5}{230}=45A\]


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