JEE Main & Advanced JEE Main Paper (Held On 16 April 2018)

  • question_answer
    A heating element has a resistance of \[100\Omega \]at room temperature. When it is connected to a supply of 220V, a steady current of 2A passes in it and temperature is\[{{500}^{o}}C\]more than room temperature. What is the temperature coefficient of resistance of the heating element? [JEE Main 16-4-2018]

    A) \[1\times {{10}^{-4}}{{\,}^{o}}{{C}^{-1}}\]              

    B) \[5\times {{10}^{-4}}{{\,}^{o}}{{C}^{-1}}\]

    C) \[2\times {{10}^{-4}}{{\,}^{o}}{{C}^{-1}}\]              

    D) \[0.5\times {{10}^{-4}}{{\,}^{o}}{{C}^{-1}}\]    

    Correct Answer: C

    Solution :

     We know that resistance \[R=\frac{V}{i}=\frac{220}{2}={{R}_{o}}(1+\alpha \Delta t)\] Also\[{{R}_{o}}\]is given as\[100\Omega \] Putting\[\Delta T=500\,K\] We get\[\alpha =2\times {{10}^{-4}}\]


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