A) \[s{{p}^{3}}d\]A trigonal bipyramidal
B) \[{{d}^{2}}s{{p}^{3}},\]octahedral
C) \[ds{{p}^{2}},\]square planar
D) \[s{{p}^{3}},\]tetrahedral
Correct Answer: C
Solution :
Wilkinson's catalyst is\[RhCl{{(PP{{h}_{3}})}_{3}}(ph=phenyl).\] It has square planar geometry with \[ds{{p}^{2}}\] hybridisation.
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