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JEE Main & Advanced JEE Main Paper (Held On 19 April 2014)

  • question_answer
    A gas is compressed from a volume of \[2{{m}^{3}}\]to a volume of \[1{{m}^{3}}\] at a constant pressure of \[100N/{{m}^{2}}.\]Then it is heated at constant volume by supplying 150 J of energy. As a result, the internal energy of the gas:     JEE Main Online Paper (Held On 19 April 2016)

    A) increases by 250 J           

    B) decreases by 250 J

    C) increases by 50 J              

    D) decreases by 50 J

    Correct Answer: A

    Solution :

    As we know,\[\Delta Q=\Delta u+\Delta w\] (Ist law of thermodynamics) \[\Rightarrow \]\[\Delta Q=\Delta u+P\Delta v\]or\[150=\Delta u+100(1-2)\] \[=\Delta u-100\] \[\therefore \]\[\Delta u=150+100=250J\] Thus the internal energy of the gas increases by 250 J


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