JEE Main & Advanced JEE Main Paper (Held On 19 April 2014)

  • question_answer
    The diameter of the objective lens of microscope makes an angle \[\beta \] at the focus of the microscope. Further, the medium between the object and the lens is an oil of refractive index n. Then the resolving power of the microscope     JEE Main Online Paper (Held On 19 April 2016)

    A) increases with decreasing value of n

    B) increases with decreasing value of \[\beta \]

    C) increases with increasing value of \[n\sin \beta \]

    D) increases with increasing value of\[\frac{1}{n\sin 2\beta }\]

    Correct Answer: C

    Solution :

    Resolving power of microscope, \[R.P.=\frac{2n\sin \theta }{\lambda }\] \[\lambda =\] Wavelength of light used to illuminate the object n = Refractive index of the medium between object and objective \[\theta =\] Angle


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