JEE Main & Advanced JEE Main Paper (Held On 22 April 2013)

  • question_answer
    In a series L-C-R circuit, \[\text{C}=\text{1}{{0}^{-11}}\] Farad, \[\text{L}=\text{1}{{0}^{-5}}\] Henry and \[\text{R}=100\] Ohm, when a constant D.C. voltage E is applied to the circuit, the capacitor acquires a charge \[\text{1}{{\text{0}}^{-9}}\operatorname{C}.\] The D.C. source is replaced by a sinusoidal voltage source in which the peak voltage \[{{\operatorname{E}}_{0}}\] is equal to the constant D.C voltage E. At resonance the peak value of the charge acquired by the capacitor will be :   JEE Main  Online Paper (Held On 22 April 2013)

    A)  \[{{10}^{-15}}\operatorname{C}\]                  

    B)  \[{{10}^{-6}}\operatorname{C}\]

    C)  \[{{10}^{-10}}\operatorname{C}\]                  

    D)  \[{{10}^{-8}}\operatorname{C}\]

    Correct Answer: D

    Solution :

     Not Available


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