2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced JEE Main Paper (Held On 22 April 2013)

  • question_answer
    To establish an instantaneous current of 2 A through a \[1\mu \operatorname{F}\] capacitor; the potential difference across the capacitor plates should be changed at the rate of :   JEE Main  Online Paper (Held On 22 April 2013)

    A)  \[2\times {{10}^{4}}\operatorname{V}/s\]                    

    B) \[4\times {{10}^{6}}\operatorname{V}/s\]

    C)  \[2\times {{10}^{6}}\operatorname{V}/s\]                    

    D)  \[4\times {{10}^{4}}\operatorname{V}/s\]

    Correct Answer: C

    Solution :

     As,         \[C=\frac{Q}{V}=\frac{It}{V}\] \[\Rightarrow \]               \[\frac{V}{t}=\frac{I}{C}=\frac{2}{1\times {{10}^{-6}}}\] \[=2\times {{10}^{6}}V/s\]


You need to login to perform this action.
You will be redirected in 3 sec spinner