JEE Main & Advanced JEE Main Online Paper (Held On 23 April 2013)

  • question_answer
                    A sonometer wire of length 114 cm is fixed at both the ends. Where should the two bridges be placed so as to divide the wire into three segments whose fundamental frequencies are in the ratio 1:3:4?     [JEE Main Online Paper ( Held On 23  April 2013 )

    A)                    At 36 cm and 84 cm from one end

    B)                                          At 24 cm and 72 cm from one end

    C)                                          At 48cm and 96 cm form one end

    D)                                          At 72 cm and 96 cm from one end         

    Correct Answer: D

    Solution :

                      Total length of the wire, L =114 cm \[{{n}_{1}}:{{n}_{2}}:{{n}_{3}}=\]1: 3 :4 Let \[{{L}_{1}},{{L}_{2}}\]and \[{{L}_{3}}\]be the lengths of the three parts As\[n\propto \frac{1}{L}\]  \[\therefore \]\[{{L}_{1}}:{{L}_{2}}:{{L}_{3}}=\frac{1}{1}:\frac{1}{3}:\frac{1}{4}=12:4:3\] \[\therefore \]\[{{L}_{1}}=72cm\left( \frac{12}{12+4+3}\times 114 \right)\] \[{{L}_{2}}=24cm\left( \frac{4}{19}\times 114 \right)\]   and\[{{L}_{3}}=18cm\left( \frac{3}{19}\times 114 \right)\] Hence the bridges should be placed at 72 cm and 72 + 24 =96 cm from one end.


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