question_answer

                If the time period \[t\] of the oscillation of a drop of liquid of density \[d\]radius \[r,\]vibrating under surface tension s is given by the formula \[t=\sqrt{{{r}^{2b}}{{s}^{c}}{{d}^{a/2}}.}\]It is observe that the time period is directly proportional to \[\sqrt{\frac{d}{s}.}\] The value of \[b\] should therefore be:     JEE Main Online Paper ( Held On 23  April 2013 )

A)                  \[\frac{3}{4}\]                                  

B)                                         \[\sqrt{3}\]

C)                                         \[\frac{3}{2}\]                  

D)                                         \[\frac{2}{3}\]