question_answer

                A 70 Kg man leaps vertically into the air from a crouching position. To take the leap the man pushes the pushes the ground with a constant force F to raise himself. The center of gravity rises by 0.5 m before he leaps. After the leap the c.g. rises by another 1 m. The maximum power delivered by the muscles is: (Take g=10 \[\text{m}{{\text{s}}^{\text{2}}}\]).     JEE Main Online Paper ( Held On 23  April 2013 )

A)                  \[\text{6}\text{.26}\times \text{1}{{\text{0}}^{\text{3}}}\] Watts at the start

B)                                         \[\text{6}\text{.26}\times \text{1}{{\text{0}}^{\text{3}}}\] Watts at take off

C)                                         \[\text{6}\text{.26}\times \text{1}{{\text{0}}^{\text{4}}}\] Watts at the start

D)                                         \[\text{6}\text{.26}\times \text{1}{{\text{0}}^{\text{4}}}\] Watts at take off