A) 61.0 %
B) 38.0%
C) 35.5 %
D) 41.5 %
Correct Answer: D
Solution :
Given \[e=1.60\times {{10}^{-19}}C\] \[d=9.17\times {{10}^{-11}}m\] From \[\mu =e\times d\] \[\mu =1.60\times {{10}^{-19}}\times 9.17\times {{10}^{-11}}\] \[=14.672\times {{10}^{-30}}\]% ionic character \[=\frac{\text{Observed dipole moment}}{\text{Dipole moment}\,\text{for}\,\text{100 }\!\!%\!\!\text{ }\,\text{ionic}\,\text{bond}}\] \[=41.5%\]You need to login to perform this action.
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