A) \[\operatorname{O}>\operatorname{N}>\operatorname{F}>C\]
B) \[O>\operatorname{F}>\operatorname{N}>C\]
C) \[\operatorname{F}>\operatorname{O}>\operatorname{N}>C\]
D) \[\operatorname{C}>\operatorname{N}>\operatorname{O}>\operatorname{F}\]
Correct Answer: B
Solution :
The second ionization potential means removal of electron from cat ion \[{{C}^{+}}=1{{s}^{2}}2{{s}^{2}}{{p}^{1}},{{N}^{+}}=1{{s}^{2}}2{{s}^{2}}2{{p}^{2}}\] \[{{O}^{+}}=1{{s}^{2}}2{{s}^{2}}2{{p}^{3}},{{F}^{+}}=1{{s}^{2}}2{{s}^{2}}2{{p}^{4}}\] Therefore O > F > N > C
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