A) \[R\,I<R\,Br<R\,Cl\]
B) \[R\,\,Cl>R\,\,Br>R\,\,I\]
C) \[R\,\,Br>R\,\,Cl>R\,\,I\]
D) \[R\,\,Br>R\,\,I\,\,>\,R\,\,Cl\]
Correct Answer: A
Solution :
For a given alkyl group, the order of reactivity is . \[\frac{R-I>R-Br>R-Cl>R-F}{\text{increasing}\,\text{bond}\,\text{energy}}\] decreasing halogen reactivity. This order depends on the carbon-halogen bond energy; the carbon-fluorine bond energy is maximum and thus fluorides are least reactive while carbon-iodine bond energy is minimum hence iodides are most reactive.
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