A) 0.137
B) 0.237
C) 0.435
D) 0.205
Correct Answer: B
Solution :
\[{{P}_{A}}=P_{A}^{o}\times {{x}_{A}}=\]total pressure \[\times {{y}_{A}}\] \[{{P}_{B}}=P_{B}^{o}\times {{x}_{B}}=\]total pressure\[\times {{y}_{B}}\]where x and y represents mole fraction in liquid and vapour phase respectively. \[\frac{P_{B}^{o}{{x}_{B}}}{P_{A}^{o}{{x}_{A}}}=\frac{{{y}_{B}}}{{{y}_{A}}};\frac{P_{B}^{o}(1-{{x}_{A}})}{P_{A}^{o}{{x}_{A}}}=\frac{1-{{y}_{A}}}{{{y}_{A}}}\] on putting values\[\frac{119(1-0.50)}{37\times 0.50}=\frac{1-{{y}_{A}}}{{{y}_{A}}}\]on solving \[{{y}_{A}}=0.237\]
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