JEE Main & Advanced JEE Main Online Paper (Held On 23 April 2013)

  • question_answer
                    The de Broglie wavelength of a car of mass 100 kg and velocity 36 km/hr is:                 \[(h=6.63\times {{10}^{-34}}\,Js)\]     JEE Main Online Paper ( Held On 23  April 2013 )

    A)                  \[6.626\times {{10}^{-34}}\operatorname{m}\]               

    B)                                         \[6.626\times {{10}^{-38}}\operatorname{m}\]

    C)                                         \[6.626\times {{10}^{-31}}\operatorname{m}\]               

    D)                                         \[6.626\times {{10}^{-30}}\operatorname{m}\]

    Correct Answer: B

    Solution :

                     \[\lambda =\frac{h}{mv}\] \[h=6.6\times {{10}^{-34}}J/s\]  \[m=1000kg\] \[v=36km/hr=\frac{36\times {{10}^{3}}}{60\times 60}m/\sec =10m/\sec \] \[\therefore \]\[\lambda =\frac{6.6\times {{10}^{-34}}}{{{10}^{3}}\times 10}=6.6\times {{10}^{-38}}m\]


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