2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced JEE Main Online Paper (Held On 23 April 2013)

  • question_answer
                    The rate constant of a zero order reaction is \[2.0\times {{10}^{-2}}\]mol\[{{\operatorname{L}}^{-1}}\]\[{{\operatorname{s}}^{-1}}\]. If the concentration of the reactant after 25 seconds is 0.5 M. What is the initial concentration?   JEE Main Online Paper ( Held On 23  April 2013 )

    A)                   0.5 M                  

    B)                                          1.25 M

    C)                                          12.5 M                               

    D)                                          1.0 M

    Correct Answer: D

    Solution :

                      For a zero order reaction Rate constant \[=k=\frac{a-x}{t}\] \[2\times {{10}^{-2}}=\frac{a-0.5}{25}\] \[a-0.5=0.5\] \[a=1.0M\]


You need to login to perform this action.
You will be redirected in 3 sec spinner