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JEE Main & Advanced JEE Main Paper (Held On 8 April 2017)

  • question_answer
    If\[{{(27)}^{999}}\]is divided by 7, then the remainder is: [JEE Online 08-04-2017]

    A)  3                                            

    B)  1

    C)  6                                            

    D)  2

    Correct Answer: C

    Solution :

     \[\frac{{{(28-1)}^{999}}}{7}=\frac{28\lambda -1}{7}\]                 \[\Rightarrow \frac{28\lambda -7+1-1}{7}=\frac{7(4\lambda -1)+6}{7}\]                 \[\therefore \]Rem = 6


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